[Seasar-user:18020] 【Teeda】複数のプロパティを使用したValidatorの作り方
thomas
[E-MAIL ADDRESS DELETED]
2009年 7月 17日 (金) 15:11:11 JST
Hello,
I need to get the property values in validator Class.
I followed this link
http://ml.seasar.org/archives/seasar-user/2008-April/013811.html
I got the null value.
Ths following is my Page class
@Check(messageId="E01")
public String joblevel;
public String levelname;
public String description;
This is my coding in Validator Class
UIViewRoot viewRoot = context.getViewRoot();
UIComponent levelname =
viewRoot.findComponent("layoutChildBody:joblevelmasterCreateForm:levelname");
System.out.println("UIComponent--------------------->"+levelname);
System.out.println("UIInput------------------------------->"+((UIInput)levelname));
System.out.println("Value---------------------------------->"+((UIInput)levelname).getValue());
I got the following values in Console.
UIComponent--------------------->[E-MAIL ADDRESS DELETED]
UIInput------------------------------->[E-MAIL ADDRESS DELETED]
Value---------------------------------->null
What mistake i made in my coding?
Thanks in advance,
トマス
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